start text, a, A, end text, plus, start text, b, B, end text, \rightleftharpoons, start text, c, C, end text, plus, start text, d, D, end text, K, start subscript, start text, c, end text, end subscript, K, start subscript, start text, e, q, end text, end subscript, K, start subscript, start text, c, end text, end subscript, equals, start fraction, open bracket, start text, C, close bracket, end text, start superscript, start text, c, end text, end superscript, start text, open bracket, D, close bracket, end text, start superscript, start text, d, end text, end superscript, divided by, open bracket, start text, A, end text, close bracket, start superscript, start text, a, end text, end superscript, open bracket, start text, B, end text, close bracket, start superscript, start text, b, end text, end superscript, end fraction, start text, N, O, end text, start subscript, 2, end subscript, start text, N, end text, start subscript, 2, end subscript, start text, O, end text, start subscript, 4, end subscript, start text, N, end text, start subscript, 2, end subscript, start text, O, end text, start subscript, 4, end subscript, left parenthesis, g, right parenthesis, \rightleftharpoons, 2, start text, N, O, end text, start subscript, 2, end subscript, left parenthesis, g, right parenthesis, start text, N, end text, start subscript, 2, end subscript, start text, O, end text, start subscript, 4, end subscript, left parenthesis, g, right parenthesis, start fraction, start text, m, o, l, end text, divided by, start text, L, end text, end fraction, open bracket, start text, C, close bracket, end text, start text, open bracket, D, close bracket, end text, open bracket, start text, A, end text, close bracket, open bracket, start text, B, end text, close bracket, K, start subscript, start text, p, end text, end subscript, 2, start text, S, O, end text, start subscript, 2, end subscript, left parenthesis, g, right parenthesis, plus, start text, O, end text, start subscript, 2, end subscript, left parenthesis, g, right parenthesis, \rightleftharpoons, 2, start text, S, O, end text, start subscript, 3, end subscript, left parenthesis, g, right parenthesis, K, start subscript, start text, c, end text, end subscript, equals, start fraction, open bracket, start text, S, O, end text, start subscript, 3, end subscript, close bracket, squared, divided by, open bracket, start text, S, O, end text, start subscript, 2, end subscript, close bracket, squared, open bracket, start text, O, end text, start subscript, 2, end subscript, close bracket, end fraction, K, start subscript, start text, c, end text, end subscript, equals, 4, point, 3, Q, equals, start fraction, open bracket, start text, S, O, end text, start subscript, 3, end subscript, close bracket, squared, divided by, open bracket, start text, S, O, end text, start subscript, 2, end subscript, close bracket, squared, open bracket, start text, O, end text, start subscript, 2, end subscript, close bracket, end fraction, Q, equals, K, start subscript, start text, c, end text, end subscript, start text, N, end text, start subscript, 2, end subscript, start text, O, end text, start subscript, 2, end subscript, start text, N, end text, start subscript, 2, end subscript, left parenthesis, g, right parenthesis, plus, start text, O, end text, start subscript, 2, end subscript, left parenthesis, g, right parenthesis, \rightleftharpoons, 2, start text, N, O, end text, left parenthesis, g, right parenthesis, K, start subscript, start text, c, end text, end subscript, equals, start fraction, start text, open bracket, N, O, end text, close bracket, squared, divided by, open bracket, start text, N, end text, start subscript, 2, end subscript, close bracket, open bracket, start text, O, end text, start subscript, 2, end subscript, close bracket, end fraction, 3, point, 4, times, 10, start superscript, minus, 21, end superscript, open bracket, start text, N, end text, start subscript, 2, end subscript, close bracket, equals, open bracket, start text, O, end text, start subscript, 2, end subscript, close bracket, equals, 0, point, 1, start text, M, end text, start text, N, O, end text, left parenthesis, g, right parenthesis, K, start subscript, start text, c, end text, end subscript, equals, start fraction, start text, open bracket, N, O, end text, close bracket, squared, divided by, open bracket, start text, N, end text, start subscript, 2, end subscript, close bracket, open bracket, start text, O, end text, start subscript, 2, end subscript, close bracket, end fraction, space, space, space, space, space, space, space, space, space, space, space, space, space, space, space, space, start text, G, e, t, space, t, h, e, space, N, O, space, t, e, r, m, space, b, y, space, i, t, s, e, l, f, space, o, n, space, o, n, e, space, s, i, d, e, point, end text. Direct link to S Chung's post This article mentions tha, Posted 7 years ago. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. B We can now use the equilibrium equation and the given \(K\) to solve for \(x\): \[K=\dfrac{[H_2O][CO]}{[H_2][CO_2]}=\dfrac{(x)(x)}{(0.0150x)(0.0150x}=\dfrac{x^2}{(0.0150x)^2}=0.106\nonumber \]. If we begin with a 1.00 M sample of n-butane, we can determine the concentration of n-butane and isobutane at equilibrium by constructing a table showing what is known and what needs to be calculated, just as we did in Example \(\PageIndex{2}\). This process continues until the forward and reverse reaction rates become equal, at which time the reaction has reached equilibrium, as characterized by constant concentrations of its reactants and products (shaded areas of Figure 13.2b and Figure 13.2c). The activity of pure liquids and solids is 1 and the activity of a solution can be estimated using its concentration. A The initial concentrations of the reactants are \([H_2]_i = [CO_2]_i = 0.0150\; M\). 3) Reactants are being converted to products and vice versa. Calculate \(K\) and \(K_p\) for this reaction. The equilibrium constant expression must be manipulated if a reaction is reversed or split into elementary steps. What is the \(K_c\) of the following reaction? When there are multiple steps in the reaction, each with its own K (in a scenario similar to Hess's law problems), then the successive K values for each step are multiplied together to calculate the overall K. Because the concentration of reactants and products are not dimensionless (i.e. Under these conditions, there is usually no way to simplify the problem, and we must determine the equilibrium concentrations with other means. \(2SO_{2(g)} + O_{2(g)} \rightleftharpoons 2SO_{3(g)} \), \(N_2O_{ (g)} + \dfrac{1}{2} O_{2(g)} \rightleftharpoons 2NO_{(g)} \), \(Cu_{(s)} + 2Ag^+_{(aq)} \rightleftharpoons Cu^{+2}_{(aq)} + 2Ag_{(s)} \), \(CaCO_{3 (g)} \rightleftharpoons CaCO_{(s)} + CO_{2 (g)} \), \(2NaHCO_{3 (s)} \rightleftharpoons Na_2CO_{3 (s)} + CO_{2 (g)} + H_2O_{ (g) }\).

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